Question

Calculate the gravitational force between a 4.0 x 10^8 kg mass and a 2.8 x 10^5 kg mass separated by a distance of 1.0 x 10^4 m.

Answer 1

`F_(g)=7.4704*10^(-5)`

Step-by-step explanation:

Givens: d = 1.0 ×
`10^(4)`
`m_(1) = 4.0 x 10^(8)`
`m_(2) = 2.8`×
`10^(5)`

Required:
`F_(g)=?`

Formula:
`F_(g)= ((6.67x10^(-11))(m_(1))(m_(2)) )/(d^(2))` (6.67x10^-11 is the gravitational constant)

`F_(g)=(\left(6.67\cdot10^(-11)\right)\left(4.0\cdot10^(8)\right)\left(2.8\cdot10^(5)\right))/(\left(1.0\cdot10^(4)\right)^(2))`

`F_(g)=7.4704*10^(-5)`