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A ball weighing 3.4 N is thrown with a velocity of 52 m/s. What is the momentum?

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6 votes

Final answer:

The momentum of a ball weighing 3.4 N and thrown at a velocity of 52 m/s is calculated as approximately 18.0 kg·m/s after determining its mass from its weight.

Step-by-step explanation:

To calculate the momentum of an object, we use the formula P = m × v, where P is momentum, m is mass, and v is velocity. Since the weight of the ball is given, we can calculate the mass by dividing weight by the acceleration due to gravity (g = 9.8 m/s2). The mass (m) of the ball weighing 3.4 N is m = 3.4 N / 9.8 m/s2 = 0.347 kg (approximately).

The ball's velocity (v) is given as 52 m/s. Thus, the ball's momentum is then P = 0.347 kg × 52 m/s = 18.044 kg·m/s, which we can round off to 18.0 kg·m/s for simplicity.

User ChrisSwires
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1 vote

Answer:

18 kg * m/s

Step-by-step explanation:

The equation for momentum is:

momentum = mass * velocity

And although the problem already gave velocity, you must calculate the mass from the graviational force.

Fg = 3.4N = mg = 9.8m

mass = 3.4 N / 9.8 m/s^2 = 0.3469 kg

Momentum = 52m/s * 0.3469 kg - 18.041 kg * m/s = 18

User Julien Carsique
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