Question

Help!!!

prove triangle PAB is an equilateral triangle

HELP PLEASEE

Answer 1

In ∆PAM and ∆PBM

`\because\pink{\sf\begin{cases} \sf AM=BM(Bisected\:by\:PM)\\ \sf PA=PB(Given)\\ \sf PM(Common\:side)\end{cases}}`

`\\ \sf\longmapsto ∆PAM\cong ∆PBM(SSS)`

`\\ \sf\longmapsto PA+AM=PB+BM`

• Put AM =BM

`\\ \sf\longmapsto PA+AM+AM=PB+BM+BM`

• Put PA=PB

`\\ \sf\longmapsto PA+AB=PB+AB`

Hence

∆APB is a equilateral triangle

Answer 2

If three sides of a triangle are equal and the measure of all three angles is equal to 60 degrees then the triangle is an equilateral triangle. Therefore it is an equilateral triangle.