Question

1. (5 points) (a) A wall clock has a pendulum that oscillates once every two seconds here on Earth. What will be the period of the clock if taken to the surface of Venus, where the acceleration due to gravity is 0.904 g

Answer 1

2.1 sec

Step-by-step explanation:

We have the time of oscillation to be T = 2 seconds

We use this formula to get the length of of the pendulum

T = 2pi√l/g

g = 9.8m/s

When we insert this value into the formula above,

2 = 2 pi√l/9.8

The value of pi = 3.14

L is the unknown

When we solve this out we will get

L = 0.993m

This is the length of the pendulum

On venus, g = 0.904

T = 2 pi√0.993/0.904(9.8)

= 2.1035s