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Y=x^2 - x - 3, y=-3X + 5. What are the solutions Of this system of equations?
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Y=x^2 - x - 3, y=-3X + 5. What are the solutions Of this system of equations?

User Tom Peplow
by
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1 Answer

2 votes

Answer:
(x,y)=\{(-4,17), (2,-1) \}

Explanation:


x^2 -x-3=-3x+5\\\\x^2 +2x-8=0\\\\(x+4)(x-2)=0\\\\x=-4, 2\\\\x=-4 \longrightarrow y=17\\\\x=2 \longrightarrow y=-1\\\\\therefore (x,y)=\{(-4,17), (2,-1) \}

User Greg Dean
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