Question

Consider the line y=-5/6x-4.

Find the equation of the line that is parallel to this line and passes through the point (-6,-2).

Find the equation of the line that is perpendicular to this line and passes through the point (-6,-2).

Answer 1

Lines that are parallel have the same gradient.

Since the line is y=-5/6x-4,the gradient of the line parallel to this line is also -5/6.

So the equation of the line parallel to y=-5/6x-4 is y-(-2)=-5/6(x-(-6))--->y=-5/6x-7.

Lines that are perpendicular fulfill the requirement: gradient 1×gradient 2=-1 . Then once you find the gradient of the line, you can find the equation of the line.