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Solve for x: 3√5x² +25x-10√√5 = 0

User Tejas
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2 Answers

8 votes


3 √(5) {x}^(2) + 25x - 10 √(5) = 0 \\ \\ 3 √(5) {x}^(2) + 30x - 5x - 10 √(5) = 0 \\ \\ 3x( √(5) x + 10) - √(5) ( √(5) + 10) = 0 \\ \\ ( √(5) x + 10)(3x - √(5) ) = 0


√(5) x + 10 = 0 \\ \\ √(5)x = - 10 \\ \\ x = ( - 10)/( √(5) ) \\ \\ x = ( - 2 * √(5 ) * √(5) )/( √(5) ) \\ \\ x = - 2 √(5) .


3x - √(5) = 0 \\ \\ 3x = √(5) \\ \\ x = ( √(5) )/(3) .

The values of x are -25 & 5/3 .

User Michaella
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8 votes

Answer: x = - 2√5, √5/3

Step-by-step explantion

3 √ 5 x 2 + 25 x − 10 √ 5 = 0 35x2+25x−105=0

⇒ 3√5x2 + 30x – 5x – 10√5 = 0

⇒ 3√5x(x + 2√5) – 5(x + 2√5) = 0

⇒ (x + 2√5)(3√5x – 5) = 0

x = - 2√5, √5/3

User SahalMoidu
by
8.6k points

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