The function f(t)=290(0.91)^{t}f(t)=290(0.91) t represents the change in a quantity over t months. What does the constant 0.91 reveal about the rate of change of the quantity? If you don't know the answer

asked Aug 15, 2021 2.9k views

2 votes

$The function f(t)=290(0.91)^{t}f(t)=290(0.91) t represents the change in a quantity-example-1$

by Rafee

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5 votes

Answer:

The function is decaying exponentially at a rate of 9% every month.

Step-by-step explanation: there you go bro

Marcelo Vismari answered Aug 22, 2021

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