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Consider the following System:

Line 1: 2x - y = -3
Line 2: -6x - 2y = -6
Is (0, 3) a solution to Line 1?

Yes
No

Consider the following System: Line 1: 2x - y = -3 Line 2: -6x - 2y = -6 Is (0, 3) a-example-1
User Alezis
by
8.1k points

1 Answer

2 votes

Answer:

YES

Explanation:

Given the equations representing two lines:

2x - y = -3 ----› Equation 1

-6x - 2y = -6 -----› Equation 2

Multiply equation 1 by 2, and multiply equation 2 by 1.

2x - y = -3 ----› Equation 1 × 2

-6x - 2y = -6 -----› Equation 2 × 1

4x - 2y = -6

-6x - 2y = -6

Subtract both equations

10x = 0

Divide both sides by 10

x = 0/10

x = 0

Substitute x = 0 into equation 1

2x - y = -3

2(0) - y = -3

0 - y = -3

-y = -3

Divide both sides by -1

y = 3

Thus, the solution would be (0, 3).

User Pjama
by
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